Answer:
0.6 is the probability of success of a single trial of the experiment
Complete Problem Statement:
In a binomial experiment with 45 trials, the probability of more than 25 successes can be approximated by [tex]P(Z>\frac{(25-27)}{3.29})[/tex]
What is the probability of success of a single trial of this experiment?
Options:
Step-by-step explanation:
So to solve this, we need to use the binomial distribution. When using an approximation of a binomially distributed variable through normal distribution , we get:
[tex]\mu =\frac{np}{\sigma}[/tex]=[tex]\sqrt{np(1-p)}[/tex]
now,
[tex]Z=\frac{X-\mu}{\sigma}[/tex]
so,
by comparing with [tex]P(Z>\frac{(25-27)}{3.29})[/tex], we get:
μ=np=27
[tex]\sigma=\sqrt{np(1-p)}[/tex] =3.29
put np=27
we get:
[tex]\sigma=\sqrt{27(1-p)}[/tex] =3.29
take square on both sides:
10.8241=27-27p
27p=27-10.8241
p=0.6
Which is the probability of success of a single trial of the experiment