Respuesta :
Answer:
public class DivisionBy6or7 {
public static int funSum1(int n){
int sum = 0;
for (int i = 6; i <= n; i++){
if(i % 6 == 0 || i % 7 == 0){
sum = sum + i;
}
}
return sum;
}
public static int funSum2(int n){
int sum = 0;
int i = 6;
while (i <= n){
if(i % 6 == 0 || i % 7 == 0){
sum = sum + i;
}
i++;
}
return sum;
}
public static int funSum3(int n){
int sum = 0;
int i = 6;
do{
if(i % 6 == 0 || i % 7 == 0){
sum = sum + i;
}
i++;
}while(i <= n);
return sum;
}
public static int funSum4(int n){
if (n < 6){
return 0;
}
else{
if(n % 6 == 0 || n % 7 == 0){
return n + funSum4(n-1);
}
else{
return funSum4(n-1);
}
}
}
public static void main(String[] args) {
System.out.println("funSum1(20) = " + funSum1(20));
System.out.println("funSum2(20) = " + funSum2(20));
System.out.println("funSum3(20) = " + funSum3(20));
System.out.println("funSum4(20) = " + funSum4(20));
}
}
Explanation:
=> function funSum1()
public static int funSum1(int n){
// initialize an int variable sum to zero to cumulatively
// find and store the sum of the integers
int sum = 0;
// write a for loop that goes from i = 6 to i = n
// At every cycle of the loop, check if i is divisible by 6 or 7
// If it is, add it to the value of sum
for (int i = 6; i <= n; i++){
if(i % 6 == 0 || i % 7 == 0){
sum = sum + i;
}
}
return sum; // Return the value of sum
} // End of method funSum1
=> function funSum2()
public static int funSum2(int n){
// initialize an int variable sum to zero to cumulatively
// find and store the sum of the integers
int sum = 0;
// write a while loop that goes from i = 6 to i = n
// At every cycle of the loop, check if i is divisible by 6 or 7
// If it is, add it to the value of sum
int i = 6;
while (i <= n){
if(i % 6 == 0 || i % 7 == 0){
sum = sum + i;
}
i++;
}
return sum;
}
=> function funSum3()
public static int funSum3(int n){
// initialize an int variable sum to zero to cumulatively
// find and store the sum of the integers
int sum = 0;
// write a do..while loop that goes from i = 6 to i = n
// At every cycle of the loop, check if i is divisible by 6 or 7
// If it is, add it to the value of sum
int i = 6;
do{
if(i % 6 == 0 || i % 7 == 0){
sum = sum + i;
}
i++;
}while(i <= n);
return sum;
}
=> function funSum4()
// The method recursively calls itself
public static int funSum4(int n){
// check if the value of n is less than 6.
// If it is, return 0
if (n < 6){
return 0;
}
// If the value of n is not less than 6,
// do the following
else{
// Check if the value of n is divisible by 6 or 7
// If it is, return n, reduce n by 1 and recall funSum4 using the
// reduced value of n
if(n % 6 == 0 || n % 7 == 0){
return n + funSum4(n-1);
}
// If the values of n is not divisible by 6 or 7,
// reduce n by 1 and recall funSum4 using the reduced value of n
else{
return funSum4(n-1);
}
}
}
=> function main()
// This is the main method of the program
// This is where java begins its execution
// The four functions are being called and tested here.
public static void main(String[] args) {
System.out.println("funSum1(20) = " + funSum1(20));
System.out.println("funSum2(20) = " + funSum2(20));
System.out.println("funSum3(20) = " + funSum3(20));
System.out.println("funSum4(20) = " + funSum4(20));
}
Output:
> funSum1(20) = 57
> funSum2(20) = 57
> funSum320) = 57
> funSum4(20) = 57
Notes:
The source code of this code has been attached to this response. Please download it for better formatting and readability.
Following are the solution to the given question:
Program Explanation:
- Declaring header file.
- Defining four methods "funSum1, funSum2, funSum3, and funSum4" that takes an integer "n" in its parameter.
- Inside the method, a loop has defined that use if block that checks "n%6" and "n%7" value equal to 0 with using OR logical gate, and use sum variable that adds value in "i".
- return sum value.
- Outside the method calling the above method and prints its value.
Program:
#include //header file
int funsum1(int n)//defining a method funsum1 that takes one integer variable inside the parameter
{
int sum=0,i=0;//defining integr variable sum and i that initializes with 0
for(i=0;i<=n;i++)//defining for loop that check value
{
if(i%6==0 || i%7==0)//defining if block that check n % 6 and n % 7 value equal to 0 with using OR logical gate
sum+=i;//defining sum variable that adds value in i
}return sum;//using return keyword that prints sum variable value
}
int funsum2(int n)//defining a method funsum2 that takes one integer variable inside the parameter
{
int sum=0,i=0;//defining integr variable sum and i that initializes with 0
while(i<=n)//defining loop that check i value less than equal to n
{
if(i%6==0 || i%7==0)//defining if block that check n % 6 and n % 7 value equal to 0 with using OR logical gate
sum+=i;//defining sum variable that adds value in i
i++;//incrementing the value of i
}return sum;//using return keyword that prints sum variable value
}
int funsum3(int n)//defining a method funsum3 that takes one integer variable inside the parameter
{
int sum=0,i=0;//defining integr variable sum and i that initializes with 0
do//defining do while loop
{
if(i%6==0 || i%7==0)//defining if block that check n % 6 and n % 7 value equal to 0 with using OR logical gate
sum+=i;//defining sum variable that adds value in i
i++;//incrementing i value
}
while(i<=n);//defining loop that check i value less than equal to n
return sum; //using return keyword that prints sum variable value
}
int funsum4(int n)//defining a method funsum4 that takes one integer variable inside the parameter
{
if(n==0)//defining if block that check n value equal to 0
return 0;//return value 0
if(n%6==0 || n%7==0)//defining if block that check n % 6 and n % 7 value equal to 0 with using OR logical gate
return n+funsum4(n-1);//using return keyword that calls funsum4 and return its value
return funsum4(n-1); //using return keyword that calls funsum4 and return its value
}
int main()//defining main method
{
printf("funsum1(20)=%d\n",funsum1(20));//calling the method and print its return value
printf("funsum2(20)=%d\n",funsum2(20));//calling the method and print its return value
printf("funsum3(20)=%d\n",funsum3(20));//calling the method and print its return value
printf("funsum4(20)=%d\n",funsum4(20));//calling the method and print its return value
return 0;
}
Output:
Please find the attached file.
Learn more:
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