Answer:
t = 16.7s
Using the the acceleration for the airplane as above, that is
a = 12 ft/s²
Now,
let t = the time it takes for the airplane to reach that take off speed
Vo = 0 ft/s (see explanation below)
V = 200ft/s
V = Vo + at (see explanation below)
t = (200ft/s - 0 ft/s) / 12ft/s²
t = 200ft/s / 12ft/s²
t = 16.7 seconds
Explanation:
The solution to this problem assumes that the force propelling the airplane forward is constant, and as a result the acceleration too must be constant.
If the acceleration of the airplane is constant, then the equations of constant acceleration motion applies here so V = Vo + at
The initial speed, Vo, is equal to zero because the airplane was in a brakes locked position and so it starts its motion before take-off from rest.
Thank you for reading and I hope this was helpful to you.
