Question

A machine gun fires 21.4 g bullets at a speed of 1160 m/s. The gun fires 215 bullets/min. What is the average force the shooter must exert to keep the gun from moving

Answer 1

Answer:

The average force exerted is 88.9 N.

Explanation:

Given that,

Mass of bullets =21.4 g

Speed = 1160 m/s

Number of bullet per min = 215

We need to calculate the average force

Using formula of force

$F=v\times rate\ of\ mass$

Where, v = speed

Put the value into the formula

$F=1160\times\dfrac{21.4\times215}{1000\times60}$

$F=88.9\ N$

Hence, The average force exerted is 88.9 N.