Question

Clark’s mass is 65 kg and Lana’s mass is 45 kg. If they are seated 2.0 m apart in their physics class, what is the force of gravitational attraction between Clark and Lana?

Answer 1

Answer:

Force of gravity, $F=4.87\times 10^{-8}\ N$

Explanation:

Mass of Clark, $m_1=65\ kg$

Mass of Lana, $m_2=45\ kg$

Distance between Clark and Lana, d = 2 m

We need to find the force of gravitational attraction between Clark and Lana. It is given by the formula as follows :

$F=G\dfrac{m_1m_2}{d^2}$

G is universal gravitational constant

$F=6.67\times 10^{-11}\times \dfrac{65\times 45}{(2)^2}$

$F=4.87\times 10^{-8}\ N$

So, the force of gravity attraction between Clark and Lana is $4.87\times 10^{-8}\ N$. Hence, this is the required solution.