Question

Which expressions show the volume and the surface area of this cube-shaped packing box?
Math item stem image
CLEAR CHECK

=(135)3 in.3; =3·(135)2 in.2
V
=
13
5
3

i
n
.
3
;

S
A
=
3
·
13
5
2

i
n
.
2


=(135)3 in.3; =6·(135)2 in.2
V
=
13
5
3

i
n
.
3
;

S
A
=
6
·
13
5
2

i
n
.
2


=6·(135)3 in.3; =(135)2 in.2
V
=
6
·
13
5
3

i
n
.
3
;

S
A
=
13
5
2

i
n
.
2


=3·(135)3 in.3; =6·(135)2 in.2

Answer 1

Answer:

The volume =$(\frac{13}{8})^3$ $feet^3$ and Surface area is $6(\frac{13}{8})^2$ $feet^2$

Step-by-step explanation:

Given:

The side of the cube = $1\frac{5}{8}$ feet

To Find:

volume = ?

surface area = ?

Solution:

Step 1: Finding the surface area of the cube shaped packing box

We know that the volume of the cube is

=> $6a^2$

On Substituting the value

surface area of the box

=> $6(1\frac{5}{8})$

=>$6(\frac{8 + 5}{8})^2$

=>$6(\frac{13}{8})^2$ $feet^2$

Step 1: Finding the volume  of the cube shaped packing box

We know that the volume of the cube is

=>$(a)^3$

On Substituting the value

Volume of the box

=>$( 1\frac{5}{8})^3$

=>$(\frac{8+5}{8})^3$

=>$(\frac{13}{8})^3$ $feet^3$