Question

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Answer 1

Answer:

$y=(\frac{1}{3})^{x}$ is decreasing exponential functions as $0<\frac{1}{3} <1$.

Step-by-step explanation:

Let

$f(x)=a^{x}$

As exponentiation increase or decrease depends upon the base value.

So,

If

$a>1, f(x)$  $is\:increasing$          

and if

$0<a<1, f(x)$  $is\:decreasing$

So,

Considering the given exponentiation function

$y=(\frac{1}{3})^{x}$

As

$0<\frac{1}{3} <1$

So, $y=(\frac{1}{3})^{x}$ is decreasing exponential functions.

In all other options, the value of base is greater than 1. i.e. $a>1$.

Therefore, $y=(\frac{1}{3})^{x}$ is decreasing exponential functions.

The graph of decreasing exponential function i.e. $y=(\frac{1}{3})^{x}$ is also attached.

Keywords: exponential function, decreasing exponential function

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