Question

Homes may be heated by pumping hot water through radiators. What mass of water will provide the same amount of heat when cooled from 95.0 to 35.0 °C, as the heat provided when 100 g of steam is cooled from 110 °C to 100 °C.

Answer 1

Answer:

mass of water is 7.43 g

Explanation:

q = mc∆T

qsteam = 100 g × 1.864 J/(g °C) × (110 – 100) °C = 1864 J

qwater = mwater× 4.184 J/(g °C) × (95 – 35) °C = mwater× 251.04 J/g = qsteam = 1864 J

mwater = 1864 J / 251.04 J/g = 7.43 g