Question

when the elevator is moving upwards but its slowing to a stop at the top floor. what is the direction of the net force on the rider?

Answer 1

Answer:Downward

Explanation:

As elevator is moving upward but is decelerating to stop at top

Suppose mg is the weight of man

N is the normal reaction

a is the acceleration

$F_{net}=N-mg=m(-a)$

here upward direction is positive while downward direction is negative

Therefore net force is in downward direction