Question

its an edge question
If f(x) = 1 – x, which value is equivalent to |f(i)|?
0
1
square root of 2
square root of -1

Answer 1

Answer:

a) The value of If(i)I  =  √2.

Step-by-step explanation:

Here the given function is f(x) = 1 -  x

To Find: If(i)I

First;y, let us find the value of f(i).

Substituting x  = i in f(x) , we get:

f(i)  = 1- i

Now, The modulus value of a function P = A + B is written as :

$IPI = IA+BI = \sqrt{A^2 + B^2}$

So, here calculating the value of If(i)I :

$I1-iI = \sqrt{(1)^2 + (-1)^2} = \sqrt{1+ (1)} = \sqrt {1+1} = \sqrt{2}\\\implies I1-iI = \sqrt{2}$

⇒ I1-1I = √2

or, If(i)I =√2

Hence, the value of If(i)I  for f(x) = 1 -x is√2.