A technician connects one lead of a digital voltmeter to the positive ( ) terminal of the battery and the other meter lead to the battery terminal (B) of the starter solenoid and then cranks the engine. During cranking, the voltmeter displays a reading of 878 millivolts. Technician A says that this reading indicates that the positive battery cable has too high resistance. Technician B says that this reading indicates that the starter is defective. Which technician is correct

A. Technician B only
B. Technician A only
C. Both Technician A and Technician B
D. Neither Technician A nor Technician B

The true resistance of a circuit is shown by voltage drop since high voltage drop indicates high resistance while low voltage drop shows low resistance of a circuit. For our case in the question, the voltage drop should not exceed 200 millivolts during cranking but we realize a reading of 878 millivolts in the voltmeter, a clear indicator of high resistance. This implies that the positive battery cable has too high resistance but not a sign of defect in the system. Therefore, technician A is correct.