Answer:
[tex]5.731\times 10^{-5}\ m/s[/tex]
Decrease
Explanation:
I = Current = 3.7 A
e = Charge of electron = [tex]1.6\times 10^{-19}\ C[/tex]
n = Conduction electron density in copper = [tex]8.49\times 10^{28}\ electrons/m^3[/tex]
[tex]v_d[/tex] = Drift velocity of electrons
r = Radius = 1.23 mm
Current is given by
[tex]I=neAv_d\\\Rightarrow v_d=\dfrac{I}{neA}\\\Rightarrow v_d=\dfrac{3.7}{8.49\times 10^{28}\times 1.6\times 10^{-19}\times \pi (1.23\times 10^{-3})^2}\\\Rightarrow v_d=5.731\times 10^{-5}\ m/s[/tex]
The drift speed of the electrons is [tex]5.731\times 10^{-5}\ m/s[/tex]
[tex]v_d=\dfrac{I}{neA}[/tex]
From the equation we can see the following
[tex]v_d\propto \dfrac{1}{n}[/tex]
So, if the number of conduction electrons per atom is higher than that of copper the drift velocity will decrease.