Question

In the following code, what is the first line that introduces a memory leak into the program?

1: #include
2: #include
3:
4: int main(void)
5: {
6: int *numbers1 = NULL;
7: int *numbers2;
8:
9: numbers1 = malloc(sizeof(int));
10: numbers2 = malloc(sizeof(int) * 12);
11:
12: *numbers1 = 0;
13: numbers2 = numbers1;
14: numbers1 = malloc(sizeof(int) * 40);
15:
16: return 0;
17: }

Answer 1

Answer:

The answer is "Line 13".

Explanation:

In the given code first, a header file is included for using basic function, In the next line the main method is defined in this method two-pointer variable is declared that is "numbers1 and numbers2", in which variable numbers1 holds a value that is "NULL".

• In the next line, both variable uses malloc() function that is used to allocate memory in heap, and in this function, sizeof() function is used that print its size and also increase its value.
• In the next step, a pointer variable numbers1 assigns a value and another variable numbers2 assigns numbers1 variable value and changes the numbers1 variable.