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A 20.0%(m/m) solution of NaOH (FM 40.00) has a density of 1.219 g/cm'. Calculate the solution's molarity. (6.10 M) 2. * 10 W= amountiof solute d- density of solution motanty m= molecular mass ot solute %3D

Respuesta :

Answer:

Molarity: [tex]M=6.095 M[/tex]

Explanation:

Base of calculation: 100 g of solution

Ammount of solute: [tex]W=0.2*100 g=20 g[/tex]

Moles of solute: [tex]n=\frac{W}{m}=\frac{20 g}{40 g/mol}=0.5 mol[/tex]

Solution volume: [tex]V=\frac{100 g}{d}=\frac{100 g}{1.219 g/cm^3}[/tex]

[tex]V=82.03 cm^3=0.08203 L[/tex]

Molarity: [tex]M=\frac{n}{V}=\frac{0.5 mol}{0.08203 L}=6.095 M[/tex]

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