corrected question:
Determining Density and Using Density to Determine Volume or Mass
(a) Calculate the density of mercury if 1.00 × 10 g occupies a volume of 7.36 cm³
(b) Calculate the volume of 65.0 g of liquid methanol (wood alcohol) if its density is 0.791 g/mL.
(c) What is the mass in grams of a cube of gold (density = 19.32 g/cm) if the length of the cube is 2.00 cm?
(d) Calculate the density of a 374.5-g sample of copper if it has a volume of 41.8 cm³ A student needs 15.0 g of ethanol for an experiment. If the density of ethanol is 0.789 g/mL, how many milliliters of ethanol are needed? What is the mass, in grams, of 25.0 mL of mercury (density = 13.6 g/mL)?
Answer:
density = [tex]\frac{mass}{volume}[/tex]
ρ=m/v ,m=ρv, v=m/ρ
(a)m=1*10g , v=7.36cm³
ρ=10/7.36 =1.36g/cm³
(b) m=65g, ρ=0.791 g/mL.
v= 65/0.791 =82.17g/mL
(c) ρ=19.32g/cm³, l=2cm, v=l³=8cm³
m=19..32*8=154.56g/cm³
(d) mass of copper=374.5g , v=41.8cm³
ρ=374.5/41.8 =8.96g/cm³
mass of ethanol=15g, density of ethanol=0.789g/mL
v=15/0.789 =19.01mL
volume of mecury=25mL, density of mercury=13.6g/mL
m=25*13.6=340g
Answer:
Explanation:
A) Given mass of mercury = [tex]100 grams[/tex]
Volume of mercury = [tex]7.36 cm^3[/tex]
Hence,
[tex]density = \frac{Mass}{Volume}\\\\ density = \frac{100}{7.36} \\\\density = 13.59 g/cm^3[/tex]
B) Given mass = [tex]65 grams[/tex]
Density = [tex]0.791 g/mL[/tex]
Hence,
[tex]volume = \frac{Mass}{Density}\\\\ volume = \frac{65}{0.791} \\\\volume = 82.17 ml[/tex]
C) Given density = [tex]19.32 g/cm3[/tex]
Side of the cube = [tex]2 cm[/tex]
Hence,
[tex]volume of the cube = Side*Side*Side\\\\ volume = 2*2*2 \\\\volume = 8 cm^3[/tex]
Thus,
[tex]mass of the cube = Volume*Density\\\\ mass = 8*19.32 \\\\mass = 154.56 grams[/tex].
D) [tex]density = \frac{Mass}{Volume}[/tex]
[tex]density = \frac{374.5}{41.8}\\\\density = 8.95g/cm^3[/tex]
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