Answer: The equation of the sphere with the center and radius
[tex]x^{2} +y^{2} +z^{2}-6 x+18 y-6 z+74=0[/tex]
b) The intersection of this sphere with the y z-plane the x- co-ordinate
is zero(i.e., x = 0 )
Step-by-step explanation:
a) The equation of the sphere having center (h,k,l) and radius r is
[tex](x-h)^{2} +(y-k)^2+(z-l)^2 = r^2[/tex]
Given center of the sphere (3, -9, 3) and radius 5
[tex](x-3)^{2}+(y+9)^2+(z-3)^2 = 5^2[/tex]
on simplification , we get solution
[tex]x^{2} -6 x+9+y^{2} +18 y+81+z^{2}-6 z+9=25[/tex]
[tex]x^{2} +y^{2} +z^{2}-6 x+18 y-6 z+74=0[/tex]
Final answer :-
[tex]x^{2} +y^{2} +z^{2}-6 x+18 y-6 z+74=0[/tex]
b) The intersection of this sphere with the y z-plane the x- co-ordinate
is zero(i.e., x = 0 )
[tex]y^{2} +z^{2}+18 y-6 z+74=0[/tex]