Answer:
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Explanation:
The volume of 99 % isopropyl alcohol in the carbomer suspension has been 40 mL.
The dilution to the concentrated solution has been prepared by as:
[tex]M_1V_1=M_2V_2[/tex]
The concentration of final alcohol solution required is [tex]M_2=66\;\%[/tex]
The volume of final solution prepared is [tex]V_2=60\;\rm mL[/tex]
The concentration of initial alcohol solution has been, [tex]M_1=99\;\%[/tex]
Substituting the values for the volume of initial solution ([tex]V_1[/tex]) required in the suspension has been,
[tex]99\;\times\;V_1=66\;\times\;60\;\text{mL}\\\\V_1=\dfrac{66\;\times\;60}{99} \;\text{mL}\\\\V_1=40\;\rm mL[/tex]
The volume of 99 % isopropyl alcohol in the carbomer suspension has been 40 mL.
Learn more about dilution, here:
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