Answer
given,
speed of plane in east, v_e = 215 Km/hr
speed of wind in north, v_w = 65 Km/hr
a) velocity of plane w.r.t. to ground
resultant of the velocity
[tex]V =\sqrt{v_e^2 +v_w^2}[/tex]
[tex]V =\sqrt{215^2 +65^2}[/tex]
V = 225 Km/h (approximately)
angle w.r.t to ground
[tex]\theta = tan^{-1}\dfrac{v_w}{v_e}[/tex]
[tex]\theta = tan^{-1}\dfrac{65}{215}[/tex]
θ = 16.82°
b) if driver want to head east
angle,
[tex]\theta = sin^{-1}\dfrac{v_w}{v_e}[/tex]
[tex]\theta = sin^{-1}\dfrac{65}{215}[/tex]
θ = 17.6°
velocity would be equal to
v = v_e cos θ
v = 215 cos 17.6°
v = 205 Km/h