A sample of 37Ar undergoes 8540 disintegrations/min initially but undergoes 6990 disintegrations/min after 10.0 days. What is the half-life of 37Ar in days?

Respuesta :

Explanation:

Expression for rate constant and half-life is as follows.

            k = [tex]\frac{1}{t} ln(\frac{a}{a - x})[/tex]

The given data is as follows.

         a = 8540 disintegrations/min

and,   (a - x) = 6990 disintegrations/min

Putting the given values into the above formula as follows.

       k = [tex]\frac{1}{10} \times ln(\frac{8540}{6990})[/tex]

           = 0.02 [tex]day^{-1}[/tex]

Now, we will calculate the half-life as follows.

      Half-life = [tex]\frac{ln 2}{k}[/tex]

                   = 34.6 days

Thus, we can conclude that the half-life of 37Ar in days is 34.6 days.

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