Question

The magnitude of the electric force between two protons is 2.30 x 10^â26N. How far apart are they?

a. 0.0220 m
b. 0.100 m
c. 0.480 m
d. 0.000570 m
e. 3.10 m

Answer 1

Answer:

The distance between two protons is 0.1 m

Explanation:

Given that,

The magnitude of force between two protons is, $F=2.3\times 10^{-26}\ N$

We know that the charge on proton is, $q_1=q_2=1.6\times 10^{-19}\ C$

If F is the electric force between two charges. It is given by the electrostatic force of attraction of repulsion. It is given by :

$F=\dfrac{kq_1q_2}{d^2}$

d is the distance between charges

$d=\sqrt{\dfrac{kq^2}{F}}$

$d=\sqrt{\dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{2.3\times 10^{-26}}}$

d = 0.1 m

So, the distance between two protons is 0.1 m. Hence, this is the required solution.