Answer:
Step-by-step explanation:
y = 1/5x + 3
in y = mx + b form, ur slope is in the m position and ur y int is in the b position
y = mx + b
y = (1/5)x + 3.....so ur slope is 1/5 and ur y int is 3 or (0,3)
to find ur x int, sub in 0 for y and solve for x
y = 1/5x + 3
0 = 1/5x + 3
-1/5x = 3
x = 3 * -5
x = -15....and ur x int is (-15,0)
so plot ur intercept points (0,3) and (-15,0)......go ahead and start at (-15,0), and since ur slope is 1/5, move up 1 space and to the right 5 spaces...plot that point.....then go up 1 and to the right 5....plot that point....keep following this pattern and u will eventually cross the x axis at (-15,0)......connect ur plotted points with a line and there u have it.
