The zeroes of the equation are (1,4)
Step-by-step explanation:
Given equation is:
[tex]y = x^2 - 5x + 4[/tex]
We have to put y=0 in the equation to find zeroes of the equation
[tex]x^2-5x+4 = 0\\x^2 - 4x- x +4 = 0\\x(x-4)-1(x-4) = 0\\(x-4)(x-1) = 0\\x - 4 =0 => x = 4\\x-1 = 0 => x = 1[/tex]
Hence,
The zeroes of the equation are (1,4)
Keywords: Equation, zeroes of an equation
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