The solution is x= 3 and y = 1
Step-by-step explanation:
Given equations are:
[tex]x-2y-1 = 0\ \ \ \ Eqn1\\y-5x+14 = 0\ \ \ \ Eqn2[/tex]
From equation 1:
[tex]x = 2y+1[/tex]
Putting in equation 2:
[tex]y - 5(2y+1)+14 = 0\\y-10y-5 +14 = 0\\-9y-5+14 = 0\\-9y+9 = 0\\-9y+9-9 = 0-9\\-9y = -9[/tex]
Dividing both sides by -9
[tex]\frac{-9y}{-9} = \frac{-9}{-9}\\y = 1[/tex]
Putting y = 1 in equation 1:
[tex]x - 2(1)-1 = 0\\x -2-1 = \\x-3 = 0\\x-3+3 = 0+3\\x = 3[/tex]
Hence,
The solution is x= 3 and y = 1
Keywords: Linear equations, polynomials
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