Answer:
The molar concentration of [tex]H^{+}[/tex] in the solution is [tex]=10^{-4}M[/tex] and Predicted molar concentration of [tex]OH^{-}[/tex] in the solution is [tex]10^{-10}[/tex]M
Explanation:
Given :
[tex]pH = - log[H^{+}]\\[/tex]
= 4
Molar concentration of [tex]H^{+}[/tex] in the solution is:
[tex][H^{+}]=10^{-pH}\\[/tex]
[tex]=10^{-4}M[/tex]
[tex][H^{+}][OH^{-}] = k_{w}[/tex]
[tex]= 10^{-14}[/tex]
Predicted molar concentration of [tex]OH^{-}[/tex] in the solution is:
[tex][OH^{-}] =\frac{[10^{-14}]}{[H^{+}]}[/tex]
= [tex]\frac{10^{-14}}{10^{-4}}[/tex]
=[tex]10^{-10}[/tex]M