Answer: 16 g
Step-by-step explanation:
We can solve this with the Radioactive Half Life Formula:
[tex]A=A_{o}.2^{\frac{-t}{h}}[/tex]
Where:
[tex]A[/tex] is the final amount of radioactive calcium
[tex]A_{o}=64 g[/tex] is the initial amount of radioactive calcium
[tex]t=10 days[/tex] is the time elapsed
[tex]h=5 days[/tex] is the half life of radioactive calcium
Solving with the given data:
[tex]A=(64 g)2^{\frac{-10 days}{5 days}}[/tex]
[tex]A=16 g[/tex] This is the amount of radioactive calcium left