can someone help me?
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Answer:
see explanation
Step-by-step explanation:
Given the width is [tex]\frac{1}{3}[/tex] of the length, then
y - 4 = [tex]\frac{1}{3}[/tex](2y + 6)
Multiply through by 3 to clear the fraction
3y - 12 = 2y + 6 ( subtract 2y from both sides )
y - 12 = 6 ( add 12 to both sides )
y = 18
Thus
length = 2y + 6 = 2(18) + 6 = 36 + 6 = 42 in
width = y - 4 = 18 - 4 = 14 in