Question

Until a train is a safe distance from the station it must travel at 5 m/s. Once the train is on open track it can speed up
to 45 m/s. If it takes a train 8 seconds to reach 45 m/s, what is the acceleration of the train? (Round your answer to
the nearest whole number)
O 4 m/s2
O 5 m/s2
O 6 m/s2
O 7 m/s2
Intro

Answer 1

Answer:

5 m/s^2

Explanation:

Initial Velocity: Vi = 5 m/s

Final Velocity: Vf = 45 m/s

Time taken from initial velocity  to reach final velocity: t = 8 sec

Since we know Acceleration: a = (Vf - Vi)/t

So a = (45 m/s - 5 m/s) / 8 s

     a = 40 m/s / 8 s

     Acceleration: a = 5 m/s^2