Answer:
36.46 g
Explanation:
Let's consider the following balanced equation.
3 Mg + N₂ → Mg₃N₂
The molar ratio of Mg to Mg₃N₂ is 3:1. The moles of Mg that produce 0.500 moles of Mg₃N₂ are:
0.500 mol Mg₃N₂ × (3 mol Mg/ 1 mol Mg₃N₂) = 1.500 mol
The molar mass of Mg is 24.305 g/mol. The mass corresponding to 1.500 moles is:
1.500 mol × (24.305 g/mol) = 36.46 g
Answer:
We need 36.45 grams of Mg
Explanation:
Step 1: Data given
Moles of Mg3N2 produced = 0.500 moles
Molar mass of Mg = 24.3 g/mol
Molar mass of Mg3N2 = 256.41 g/mol
Step 2: The balanced equation
3Mg + N2 → Mg3N2
Step 3: Calculate moles of Mg
For 3 moles of Mg we need 1 mol of N2 to produce 1 mol of Mg3N2
For 0.500 moles Mg3N2 we need 3*0.500 moles = 1.500 moles of Mg
Step 4: Calculate mass of Mg
Mass Mg = moles Mg * molar mass Mg
Mass Mg = 1.500 moles * 24.3 g/mol
Mass Mg = 36.45 grams
