Answer:
a. decrease by a factor of 3.
Explanation:
The intensity of light is inversely proportional to the square of distance.
I ∝1/d^2
or
I= k/d^2
where k is a constant
so, if d becomes 2d , I will be come I/4
Therefore, intensity will a. decrease by a factor of 3.
Answer:
option (b)
Explanation:
According to the inverse square law,
[tex]Brightness \alpha \frac{1}{distance^{2}}[/tex]
As the distance is doubles, the brightness becomes one fourth.
It means the brightness decreases by a factor of 4.
Option (b)