Question

A proton in a particle accelerator is traveling at a speed of 0.99c.(a) If you use the approximate nonrelativistic equation for the magnitude of momentum of the proton, what answer do you get?(b) What is the magnitude of the correct relativistic momentum of the proton?(c) The approximate value (the answer to part a) is significantly too low. What is the ratio of magnitudes you calculated (correct/approximate)?

Answer 1

Answer:

a)  p = 4.96 10⁻¹⁹ kg m / s , b)  p = 35 .18 10⁻¹⁹  kg m / s ,

c)  p_correst / p_approximate = 7.09

Explanation:

a) The moment is defined in classical mechanics as

                 p = m v

Let's calculate its value

               p = 1.67 10⁻²⁷ 0.99 3. 10⁸

               p = 4.96 10⁻¹⁹ kg m / s

b) in special relativity the moment is defined as

               p = m v / √(1 –v² / c²)

Let's calculate

                p = 1.67 10⁻²⁷ 0.99 10⁸/ √(1- 0.99²)

                p = 4.96 10⁻¹⁹ / 0.141

                p = 35 .18 10⁻¹⁹  kg m / s

c) the relationship between the two values ​​is

            p_correst / p_approximate = 35.18 / 4.96

            p_correst / p_approximate = 7.09

Answer 2

The Answer is:

• a) when p = 4.96 10⁻¹⁹ kg m / s ,
• b)  when p = 35 .18 10⁻¹⁹  kg m / s ,
• c)  when p_correst / p_approximate = 7.09

a) When The moment is defined in classical mechanics as

•            Then: p = m v
• Then Let's calculate its value
•              After that p = 1.67 10⁻²⁷ 0.99 3. 10⁸
•              Now, p = 4.96 10⁻¹⁹ kg m / s

b) when in special relativity the moment is defined as:

•              p = m v / √(1 –v² / c²)
• Then Let's we calculate
•               Then  p = 1.67 10⁻²⁷ 0.99 10⁸/ √(1- 0.99²)
•                 When  p = 4.96 10⁻¹⁹ / 0.141
•                Now, p = 35 .18 10⁻¹⁹  kg m / s

c) When the relationship between the two values ​​isa

•           Then  p_correst / p_approximate = 35.18 / 4.96
•           When  p_correst / p_approximate = 7.09

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