Respuesta :
The acceleration of gravity at the location is 9.64 m/s²
Explanation:
Length of pendulum = 2.5 m
Time taken for 5 swings = 16 seconds
Time taken for 1 swing = 3.2 seconds
Period of pendulum = 3.2 seconds.
We have equation for period of simple pendulum as
[tex]T=2\pi \sqrt{\frac{l}{g}}[/tex]
Where l is the length of pendulum and g is acceleration due to gravity.
Substituting
[tex]T=2\pi \sqrt{\frac{l}{g}}\\\\3.2=2\pi \sqrt{\frac{2.5}{g}}\\\\g=\frac{4\pi^2 \times 2.5}{3.2^2}\\\\g=9.64m/s^2[/tex]
The acceleration of gravity at the location is 9.64 m/s²
The acceleration of gravity at the location given pendulum is moving is 9.64 m/s.
The period of simple pendulum formula id given as
[tex]\bold {T = 2\pi \sqrt{\dfrac lg}}[/tex]
Where,
T- period = 16/5 = 3.2 sec
l - length of pendulum = 2.5 m
g- gravitational acceleration = ?
Put the values in the formula,
[tex]\bold {3.2\ s= 2\pi \sqrt{\dfrac { 2.5\ m}g}}[/tex]
[tex]\bold {g = 9.64 m/s}[/tex]
Therefore, the acceleration of gravity at the location given pendulum is moving is 9.64 m/s.
To know more about pendulum,
https://brainly.com/question/14759840
