Respuesta :

Answer:

0.1111

Step-by-step explanation:

Given that you  roll two dice.

the average of the high and low roll is exactly 3,

Since die can show only 1 to 6 we can say average can be 3 in each of the following case.

(1,5) (2,4) (3,3) (4,2) (5,1)

There cannot be any other combination to get average of 3.

Thus favourable events = 4

Sample space will have

(1,1)...(1,6)

(2,1)....

(6,1)...(6,6) i.e. 36

So probability that the average of the high and low roll is exactly 3

=[tex]\frac{4}{36} \\=0.1111[/tex]