Respuesta :
Answer:(a) 8.33m/s
(b) 1.11m/s^2
Explanation:
By using the equation of motion for the problem,
Given that V=15m/s U=?(unknown) t=6.0s S= 70m
By definition, distance is the product of the average velocity and time
From S=[(u+v)/2]xt
By substitution, 70 =[(U+15)/2]x 6
U=8.33m/s
By using V=U+at
15=6.66+6a
By substitution, acceleration=1.11m/s^2
Speed is the distance covered by the body in the time taken and acceleration is the change of velocity with respect to time.
- a) The speed at the first point is 8.33 meter per second.
- b) The acceleration of the antelope is 1.1117 meter per second squared.
Given information-
The distance between the two points is 70 m.
The time taken by the antelope to cover the distance between two points is 6.00 s.
Speed of the antelope when it passes the second point is 15.0 m/s.
What is speed?
Speed is the distance covered by the body in the time taken.
- a) Speed at the first point-
Use the equation of motion, which is,
[tex]S=\dfrac{u+v}{2} \times t[/tex]
Here [tex]S[/tex] is the distance, [tex]t[/tex] is time taken, [tex]u[/tex] is initial velocity which is equal to the speed at the first point and [tex]v[/tex] is velocity.
Put the values and ind the initial velocity,
[tex]70=\dfrac{u+15}{2} \times 6[/tex]
Solve for [tex]u[/tex],
[tex]u=\dfrac{70\times2}{6} -15\\u=23.33-15\\u=8.33[/tex]
Hence the speed at the first point is 8.33 meter per second.
What is acceleration?
Acceleration is the change of velocity with respect to time.
- b) Acceleration-
Us the equation of motion,
[tex]V=u+at\\15=8.33+a\times6[/tex]
Solve for [tex]a[/tex]
[tex]a=\dfrac{15-8.33}{6} \\a=1.1117[/tex]
Thus the acceleration of the antelope is 1.1117 meter per second squared.
Hence,
- a) The speed at the first point is 8.33 meter per second.
- b) The acceleration of the antelope is 1.1117 meter per second squared.
Learn more about the equation of motion here;
https://brainly.com/question/8898885
