Question

a) A fashionable spike heel has an area of 0.878 cm2. When a 61.4 kg woman walking in this shoe sets her full weight down on the heel, what is the pressure ?

Answer 1

Answer:

Pressure, $P=6.85\times 10^5\ Pa$

Explanation:

Given that,

Area of the heel, $A=0.878\ cm^2=0.878\times 10^{-4}\ m^2$

Mass of the woman, m = 61.4 kg

To find,

Pressure on the heel.

Solution,

The pressure acting on the heel is given by the net force acting on the box per unit area. Its formula is given by :

$P=\dfrac{F}{A}$

$P=\dfrac{mg}{A}$

$P=\dfrac{61.4\times 9.8}{0.878\times 10^{-4}}$

$P=6.85\times 10^5\ Pa$

So, the pressure exerted by the heel of the woman is $6.85\times 10^5\ Pa$. Hence, this is the required solution.

Answer 2

Answer:

Explanation:

Answer:

6853.3 Pa

Explanation:

Area, A = 0.878 cm² = 0.0878 m²

mass, m = 61.4 kg

Force, F = m x g = 61.4 x 9.8 = 601.72 N

Pressure = force / Area

Pressure, P = 601.72 / 0.0878

P = 6853.3 Pa

Thus, the pressure is 6853.3 Pa.

P = 61.4 x 9.8 / 0.878