There are 3.14 g of pentafluorobenzene is present in the sample.
It is the measurement of how much amount of substance is present in the given volume.
[tex]m = \rho \times V[/tex]
Where,
[tex]m[/tex] - mass
[tex]\rho[/tex] - dencity = 1.51 g/mL
[tex]V[/tex] - volume = 2.08 L = 2080 mL
Put the values in the formula,
[tex]m ={ \rm 1.51 \ g/mL \times 2.08 \ L}\\\\m = 3.14 \rm \ g[/tex]
Therefore, there are 3.14 g of pentafluorobenzene is present in the sample.
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