Question

9. A wire of 6.50 m long, 2.05 mm in diameter, and had a resistance at room temperature of 0.0290 ohm. Of the materials listed in the table, which is the site most likely made of?

A. steel

B. silver

C. lucite

D. lead

Answer 1

Answer: silver

Explanation:

we have to convert the diameter from millimeter to meter

Therefore 2.05mm=2.05/1000

Area= π×(d/2)^2 A=π×(2.05/1000÷2)^2

Area=3.3×10^-6

Resistivity=(resistance×area)/length

Resistivity=(0.0290×3.3×10^-6)÷6.5

Resistivity=1.47×10^-8

Answer 2

The given wire has the resistivity of $1.47x10^-^8$that is equal to the is Silver wire. Hence, the given wire is a silver wire.

Given here,

Length of wire =  6.50 m

Diameter = 2.05 mm =  radius = 1.25 mm

Resistance at RT  = 0.0290 ohm

The area of the wire,

$\bold {A = \pi r^2}\\\\\bold {A = \pi ( 1.25 mm)^2}\\\\\bold {A = 3.3 x 10^-^6}$

The resistivity of a conductor can be calculated by the formula,

$\bold {\rho = (R \times A) L}$

Where,

$\bold {\rho}$ - Resistivity

R - resistance

A - Area

L - length

Put the values in the formula,

$\bold {\rho = \dfrac {(0.0290\times 3.3x10^-^6)} {6.5}}\\\\\bold {\rho =1.47x10^-^8}$

Therefore, the given wire has the resistivity of $1.47x10^-^8$that is equal to the is Silver wire. Hence, the given wire is a silver wire.

To know more about resistivity,

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