Answer:
Explanation:
spring constant, K = 13.1 N/m
22 oscillations in 20 seconds
time taken to complete one oscillation is called time period.
T = 20 / 22 second = 0.909 seconds
(a) let m be the mass.
The formula for the time period is
[tex]T = 2\pi \sqrt{\frac{m}{K}}[/tex]
[tex]m = \frac{T^{2}K}{4\pi ^{2}}[/tex]
[tex]m = \frac{0.909^{2}\times 13.1}{4\pi ^{2}}[/tex]
m = 0.275 kg
(b) maximum speed, v = ω A = 2π A / T
v = ( 2 x 31.4 x 0.1) / 0.909
v = 0.691 m/s
