Question

The radius of the earth very nearly circular orbit around the sun is
1.50
⋅
10
11
m. What is the magnitude of the earth‘s velocity and centripetal acceleration as it travels around the sun?

Answer 1

Answer

given,

radius of earth,r = 1.5 x 10¹¹ m

Time,T = 365 days

         = 365 x 24 x 3600 s  

earth velocity,

$v=\dfrac{2\pi r}{T}$

$v=\dfrac{2\pi (1.5\times 10^{11})}{365\times 24\times 3600}$

    v = 3 x 10⁴ m/s

centripetal acceleration of the earth

 $a = \dfrac{v^2}{r}$

 $a = \dfrac{(3\times 10^4)^2}{1.5\times 10^{11}}$

        a = 6 x 10⁻³ m/s²