Answer:
[tex]|I|=21,000\ kg.m/s[/tex]
Correct answer: Option E
Explanation:
Impulse and Momentum
The Impulse is defined as the change of momentum of an object in a certain interval. The formula is:
[tex]I=\Delta p=p_f-p_o[/tex]
Where pf and po are the final and initial momentums respectively. Knowing that for m= mass of the object and v=velocity (or speed in the scalar form)
[tex]p=m.v[/tex]
Thus
[tex]I=m(v_f-v_o)[/tex]
Mr. Hogan's 3000 kg truck is initially at 36 m/s and later slows down to 29 m/s. We compute the impulse as follows
[tex]I=3000\ kg(29\ m/s-36\ m/s)[/tex]
[tex]I=3000(-7)\ kg.m/s[/tex]
[tex]I=-21,000\ kg.m/s[/tex]
We are asked for the magnitude, thus
[tex]|I|=21,000\ kg.m/s[/tex]
Correct Answer: Option E