Question

A 505-N rightward force is use to drag a large box across the floor with a constant velocity of 0.62 m/s. The coefficient of friction between the box and the floor is 0.7. Determine the mass of the box.

Answer 1

Answer:

73.62 kg

Explanation:

$F_{NET} = F_{a} + F_{f}$

$F_{NET} = 0$

Given;

$F_{a} = 505N$

$0= 505N + F_{f}$

$F_{f} = -505 N$

Also

$F_{f} = -\mu*m*g$

where m is the mass of the box,

g is acceleration due to gravity = 9.8 m/s²

$\mu$ is coefficient of friction = 0.7

-505 = - (m*0.7*9.8)

-505 = -6.86 m

m = 505/6.86

m = 73.62 kg