Answer:
The energy difference between these 2p and 2s orbitals is [tex]3.07\times 10^{-19} J[/tex]
Explanation:
Wavelength of the photon emitted = [tex]\lambda =646.3 nm =646.3\times 10^{-9} m[/tex]
Energy of the photon will corresponds to the energy difference between 2p and 2s orbital = E
Energy of the photon is given by Planck's equation:
[tex]E=\frac{hc}{\lambda }[/tex]
h = Planck's constant = [tex]6.626\tiomes 10^{-34} Js[/tex]
c = Speed of the light = [tex]3\times 10^8 m/s[/tex]
[tex]E=\frac{6.626\tiomes 10^{-34} Js\times 3\times 10^8 m/s}{646.3\times 10^{-9} m}[/tex]
[tex]E=3.07\times 10^{-19} J[/tex]
The energy difference between these 2p and 2s orbitals is [tex]3.07\times 10^{-19} J[/tex]
