Question

A force of 60 pounds stretches a spring 1 inch from its natural position. Find the work (in in-lb) done in stretching the spring from its natural length of 10 inches to double that length.

Answer 1

Answer:

50 lb

Explanation:

Force, F = 60 pounds

extension in the spring, x = 10 inch = 10 / 12 foot

Work, W = F x

W = 60 x 10 / 12 = 50 lb