Question

SAE 30 oil at 60 !F flows through a 2-in.-diameter pipe with a mean velocity of 5 ft/s. Determine the value of the Reynolds number (see Example 1.4).

Answer 1

Answer:

Re=185.39

Explanation:

Given that

d= 2 in

We know that

1 in = 0.0254 m

d = 0.0508 m

Velocity V= 5 ft/s

1 ft/s = 0.3048 m/s

V = 1.524 m/s

Lets take Density for oil ,ρ = 910 kg/m³

Dynamic viscosity ,μ = 0.38 Pa.s

We know that Reynolds number given as

$Re=\dfrac{\rho V d}{\mu}$

$Re=\dfrac{910\times 1.524\times 0.0508}{0.38}$

Re=185.39

Therefore Reynolds number will be 185.39.