Question

A vector has components Ax = 12.0 m and Ay= 5.00 m. What is the angle that vector A makes with the x-axis?a. 67.4ob. 32.6oc. 22.6od. 12.6o

Answer 1

Answer:

C.22.6°

Explanation:

Ax = ACosθ,

A = Ax/Cosθ    .....equ1

Ay = Asinθ,

A= Ay/sinθ      .....equ 2

equate equation 1 and 2.

Ax/Cosθ = Ay/sinθ

Ax = 12.0 m,  Ay= 5.00 m

12/Cosθ = 5/sinθ

θ = 22.6°

Answer 2

Vector A makes an angle of 22.6 degrees with the x-axis.

How do you calculate the angle?

Given that the vector component of A for the x-axis is Ax = 12.0 m and for the y-axis is Ay= 5.00 m.

The angle $\theta$ corresponding to the x-axis is given below.

$Ax = Acos\theta$

$A = \dfrac {Ax}{cos \theta}$

The angle $\theta$ corresponding to the y-axis is given below.

$Ay=Asin\theta$

$A = \dfrac {Ay}{sin\theta}$

Now we can write the values of A for the x-axis and y-axis as given below.

$\dfrac {Ax}{cos\theta} = \dfrac {Ay}{sin\theta}$

$Ax sin\theta = Ay cos \theta$

Substituting the values of Ax and Ay,

$12\times sin\theta = 5 \times cos\theta$

$\theta = 22.6^\circ$

Hence we can conclude that Vector A makes an angle of 22.6 degrees with x-axis.

To know more about the angle of vector, follow the link given below.

https://brainly.com/question/22363471.