Question

Calculate the charge due to all of the electrons present in 1.0 mL of pure water. (1 mL of water will contain 3.34 \times 10^{22}3.34×10 ​22 ​​ water molecules).

Answer 1

Answer:

4.8 x 10^4 C

Explanation:

number of molecules in 1 ml of water = 3.34 x 10^22

1 molecule of water contains 9 electrons

So, the number of electrons in 1 ml of water = 9 x 3.34 x 10^22

                                                                      = 30.06 x 10^22

Charge of 1 electron = 1.6 x 10^-19 C

So, the charge on 30.06 x 10^22 electrons = 1.6 x 10^-19 x 30.06 x 10^22

                                                                    = 4.8 x 10^4 C