Question

Help please! -A compound contains 0.013 moles of carbon, 0.039 moles of hydrogen and 0.0065 moles of oxygen. Determine the empirical
formula.
A) C2H601
B) C3H501
C) C4H12O2
D) CHO

Answer 1

A) C2H6O1

To find the emperical formula, divide each mole value by the smallest

For carbon, 0.013/0.0065 = 2

For hydrogen, 0.038/0.0065= 6

For oxygen, 0.0065/0.0065= 1

Emperical formula = C2H6O1

Answer 2

The empirical formula is option A) C2H6O1

Calculation of the empirical formula:

Since the compound contains 0.013 moles of carbon, 0.039 moles of hydrogen, and 0.0065 moles of oxygen.

So here we have to divide each mole from the smallest

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For carbon, 0.013/0.0065 = 2

For hydrogen, 0.038/0.0065= 6

For oxygen, 0.0065/0.0065= 1

Therefore,

Emperical formula = C2H6O1

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