Question

The electrostatic force of attraction between two charged objects separated by a distance of 1.0 cm is given by F. If the distance between the objects were increased to 5.0 cm, what would be the electrostatic force of attraction between them?
a) 5Fb) F/5c) 25Fd) F/25

Answer 1

Answer:

D. F/25

Explanation:

F= kq1q2/r² when r= 1,when r = 5,

F= F/5²

Force= F/25