Question

When spiking a volleyball, a player changes the velocity of the ball from 4.2m/s to -24m/s along a certain direction. If the impulse delivered to the ball by the player is -9.3kg . m/s, What is the mass of the volleyball?

Answer 1

Answer:

The mass of the volleyball is 0.32 kg.

Explanation:

Given that,

Initial speed of the ball, u = 4.2 m/s

Final speed of the ball, v = -24 m/s

The impulse delivered to the ball by the player is -9.3 kg-m/s.

To find,

Mass of the volleyball.

Solution,

The change in momentum of the volleyball is equal to the impulse delivered to the ball. It is given by :

$J=m(v-u)$

$m=\dfrac{J}{(v-u)}$

$m=\dfrac{-9.3\ kg-m/s}{(-24-4.2)\ m/s}$

m = 0.32 kg

So, the mass of the volleyball is 0.32 kg.

Answer 2

The momentum is equal to the delivered impulse. The mass of the given volleyball is 0.32 kg.

The momentum is equal to the delivered impulse,

J = m (v- u)

Where,

J - impulsed delivered =  -9.3kg m/s,

u - Initial speed of the ball = 4.2 m/s

v - Final speed of the ball = -24 m/s

m - mass of the object = ?

Put the value in the formula,

$\bold {-9.3\ kg\ m/s = m ( -24\ m/s - 4.2\ m/s )}\\\\\bold {m = \dfrac {-9.3\ kg\ m/s }{- 19.8\ m/s}}\\\\\bold {m = 0.32\ kg}$

Therefore, the mass of the given volleyball is 0.32 kg.

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