Answer:
The interior angles of a regular hexagon are congruent
Step-by-step explanation:
we know that
A regular polygon is a polygon that all interior angles are equal in measure, and all sides have the same length.
The sum of the measure of the interior angles in a regular polygon is equal to
[tex]S=(n-2)180^o[/tex]
where
n is the number of sides
For n=6 (hexagon)
[tex]S=(6-2)180^o\\S=720^o[/tex]
Divide by the number of sides
[tex]\frac{720^o}{6}=120^o[/tex]
In this problem we have
[tex](4x+40)^o=6x^o[/tex]
solve for x
[tex]6x-4x=40\\2x=40\\x=20^o[/tex]
Verify the measure of the interior angle in a regular hexagon with the value of x
[tex](4(20)+40)^o=120^o[/tex] ---> is ok
[tex]6(20)=120^o[/tex] ---> is ok
therefore
The interior angles of a regular hexagon are congruent