Find the sum of the measures of the interior angles:
1. Nonagon
2.Pentagon
3.11-gon
4.18.gon
5.38-gon
6.56-gon

Please show all work on how you got each answer

Respuesta :

The sum of the measures of the interior angles

The sum of interior angles of any polygon can be foud wuth the following general formula

Sum of interior angles = (n-2) \ times 180^{\circ}

where n is the number of sides

1. Nonagon

The Nonagon is a polygon with 9 sides. then,

n = 9

Sum of interior angles of Nonagon

= [tex](9-2) \times 180^{\circ}[/tex]

=[tex](7) \times 180^{\circ}[/tex]

= [tex]1260^{\circ}[/tex]

2.Pentagon

The Pentagon is a polygon with 5 sides. then,

n = 5

Sum of interior angles of Pentagon

= [tex](5-2) \times 180^{\circ}[/tex]

=[tex](3) \times 180^{\circ}[/tex]

= [tex]540^{\circ}[/tex]

3. 11-gon

The 11-gon is a polygon with 11 sides. then,

n = 11

Sum of interior angles of 11-gon

=[tex](11-2) \times 180^{\circ}[/tex]

=[tex](9) \times 180^{\circ}[/tex]

= [tex]1620^{\circ}[/tex]

4. 18-gon

The 18-gon is a polygon with 18 sides. then,

n = 18

Sum of interior angles of 18-gon

=[tex](18-2) \times 180^{\circ}[/tex]

=[tex](16) \times 180^{\circ}[/tex]

=[tex]2880^{\circ}[/tex]

5. 38-gon

The 38-gon is a polygon with 38 sides. then,

n = 38

Sum of interior angles of 38-gon

=[tex](38-2) \times 180^{\circ}[/tex]

=[tex](36) \times 180^{\circ}[/tex]

= [tex]6480^{\circ}[/tex]

6.56-gon

The 56-gon is a polygon with 56 sides. then,

n = 56

Sum of interior angles 56-gon

=[tex](56-2) \times 180^{\circ}[/tex]

=[tex](54) \times 180^{\circ}[/tex]

=[tex]9720^{\circ}[/tex]

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